n^2+2n-12.77=0

Solution for n^2+2n-12.77=0 equation:

n^2+2n-12.77=0

a = 1; b = 2; c = -12.77;
Δ = b2-4ac
Δ = 22-4·1·(-12.77)
Δ = 55.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{55.08}}{2*1}=\frac{-2-\sqrt{55.08}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{55.08}}{2*1}=\frac{-2+\sqrt{55.08}}{2}
$